Question

please solve this problem
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Answer 1

Answer:

Let acceleration of train be a, and length of train be l .

The train changes in velocity from 6 to 8 kph after traveling a distance of l while experiencing acceleration of a. Since acceleration is constant and there is no mention of time, we can use the formula

v2=u2+2as

Where v is final velocity, u is initial velocity, a is acceleration, and s is displacement(in this case, distance). Substitute the given values and we get:

82=62+2al

64−36=2al

14=al

Now, we want to find the velocity of the train when it is halfway over the point, in other words, when the distance traveled is 0.5l . We can use the same formula to calculate the velocity by using this distance.

v2=62+2a(0.5l)

v2=36+al

v=√(36+14)=√50 which is around 7.07.

Answer 2

Answer:

The old woman looked___the Children

Step-by-step explanation:

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