Math, asked by rimimandal697, 3 months ago

please solve this problem​

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Answered by nyasha10oct
0

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x3y5=(x+y)8

⇒x3(5y4dxdy)+y5(3x2)=8(x+y)7(1+dxdy)

⇒5x3y4dxdy+3x2y5=8(x+y)7+8(x+y)7dxdy

⇒(5x3y4−8(x+y)7)dxdy=8(x+y)7−3x2y5

We have x3y5=(x+y)8⇒x3y4=

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