please solve this problem
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let the common multiple be X
sum of angles in triangle is 180°
2 X+3 X+5 X = 180°
10 X = 180°
X = 180÷10
X = 18°
angles are:
2X = 2×18 = 36°
3X = 3×18 = 54°
5X = 5×18 = 72°
hope this helps you....
sum of angles in triangle is 180°
2 X+3 X+5 X = 180°
10 X = 180°
X = 180÷10
X = 18°
angles are:
2X = 2×18 = 36°
3X = 3×18 = 54°
5X = 5×18 = 72°
hope this helps you....
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