please solve this problem
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angle d is equal 90 ( square)
Bd divide angle d into 45 45
therefor by angle sum property
45 + 78 +xod= 180
xod=57
dxo+oxc= 180
78+oxc= 180
oxc=102
now,in triangle oxc
102 + 45 +xoc = 180
Bd divide angle d into 45 45
therefor by angle sum property
45 + 78 +xod= 180
xod=57
dxo+oxc= 180
78+oxc= 180
oxc=102
now,in triangle oxc
102 + 45 +xoc = 180
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