Question

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Answer 1

Answer:

6 and 2.

Step-by-step explanation:

Let the quadratic polynomial be f (x) = ax ^ 2 + bx + c and its zeroes be a and b.

Then, a + b = 8 = -b / a and ab = 12 = c / a.

If a = 1, then b = -8 and c = 12.

Hence, the quadratic polynomial is x ^ 2 - 8x + 12.

Splitting the middle term, we get:

x ^ 2 - 8x + 12 = (x - 6) (x - 2).

The zeroes of f (x) are given by f (x) = 0.

(x - 6) (x - 2) = 0

=) (x - 6) = 0 or (x - 2) = 0

=) x = 6 or x = 2.

Hence, the zeroes of f (x) are a = 6 and b = 2.

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Answer 2

Answer:

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