please solve this problem of 6th please
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Hey!!!
Good Evening
___________
let the two numbers be x and y (x > y)
Then ATQ
=> 3x = 4y + 3 (Euclid's Division Lemma chapter 1)
=> ( 3x - 4y = 3 )5
Also
=> 7y = 5x + 1
=> ( 5x - 7y = - 1 )3
Thus we have
=> 15x - 20y = 15
and
=> 15x - 21y = -3
By Elimination
=> 15x - 20y = 15
=> 15x - 21y = - 3
(-). (+). (+)
_________________
=> y = 18 <<<<<< Answer
Using y in the first equation
=> 3x - 4y = 3
=> 3x - 4(18) = 3
=> 3x = 3 + 72
=> 3x = 75
=> x = 25 <<<<<<< Answer
Thus the greater number is 25 and smaller is 18
____________
For any doubts comment below
Hope this helps ✌️
Good Night :-)
Good Evening
___________
let the two numbers be x and y (x > y)
Then ATQ
=> 3x = 4y + 3 (Euclid's Division Lemma chapter 1)
=> ( 3x - 4y = 3 )5
Also
=> 7y = 5x + 1
=> ( 5x - 7y = - 1 )3
Thus we have
=> 15x - 20y = 15
and
=> 15x - 21y = -3
By Elimination
=> 15x - 20y = 15
=> 15x - 21y = - 3
(-). (+). (+)
_________________
=> y = 18 <<<<<< Answer
Using y in the first equation
=> 3x - 4y = 3
=> 3x - 4(18) = 3
=> 3x = 3 + 72
=> 3x = 75
=> x = 25 <<<<<<< Answer
Thus the greater number is 25 and smaller is 18
____________
For any doubts comment below
Hope this helps ✌️
Good Night :-)
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