Math, asked by Anonymous, 1 year ago

Please solve this problem please it's very very very very very very very very very very very very very very very urgentttttt!
Pls do both questions

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Answered by hemantvats17
5
Q21=  Jenny will use the club every alternate day.
So, the series of the days Jenny uses the club = 1, 3, 5, 7,9 .... 359.
Let the number of days Jenny used the club be 'x'
an = a + (n-1) d
⇒ 359 = 1 + (x-1) 2
⇒ x = 180 
Sally will use the club every third day.
So, the series of days Sally uses the club = 1, 4, 7, 10, 13...... 358.
Let the number of days Sally used the club be 'y'.
an = a + (n-1) d
⇒ 358 = 1 + (y-1)3
⇒ y = 120
every sixth day both Jenny and Sally use the club together,
So, the series of days when both Jenny and Sally use together = 1, 7, 13, .... 355.
Let the total number of days when both Jenny and Sally will go to the club together be 'L'.
an = a + (n-1) d
⇒ 355 = 1 + (L-1) 6
L = 60
Total number of days they both went to the club = x + y - L
⇒ 180 + 120 - 60
= 240 days
So, the number of days when none of them gone to the club = 360 - 240
= 120 days   Answer.

Q22=  is in photo
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Answered by Anonymous
0
HERE is ur answer!!!

the answer of que no.21 is 120days...
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