please solve this problem plz
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hey friend!!?
(1) root10 =>
We can do it by using Pythagoras Theorem.
We can write √10 = √(9 + 1)
=> √10 = √(32 + 1)
Construction ☞
________-
1. Take a line segment AO = 3 unit on the x-axis. (consider 1 unit = 2cm)
2. Draw a perpendicular on O and draw a line OC = 1 unit
3. Now join AC with √10.
4. Take A as center and AC as radius, draw an arc which cuts the x-axis at point E.
(2) Since root 13=3.60
(3) root 7 =>
We know that √4 = 2
√9 = 3
√7 lies between √4 and √7
√7 lies between 2 and 3
process :
1) draw an x-axis
2) mark 0cm to 5cm
3) locate √7 somewhere between 2 and 3
hope it will help you
(1) root10 =>
We can do it by using Pythagoras Theorem.
We can write √10 = √(9 + 1)
=> √10 = √(32 + 1)
Construction ☞
________-
1. Take a line segment AO = 3 unit on the x-axis. (consider 1 unit = 2cm)
2. Draw a perpendicular on O and draw a line OC = 1 unit
3. Now join AC with √10.
4. Take A as center and AC as radius, draw an arc which cuts the x-axis at point E.
(2) Since root 13=3.60
(3) root 7 =>
We know that √4 = 2
√9 = 3
√7 lies between √4 and √7
√7 lies between 2 and 3
process :
1) draw an x-axis
2) mark 0cm to 5cm
3) locate √7 somewhere between 2 and 3
hope it will help you
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Deepsbhargav:
jodhpur
hmm
nothing
and you
hii
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