Question

please solve this problem quickly please please.

Answer 1

mark my answer brainliest

Answer 2

$\frac{3}{2} x + \frac{2}{3} y = 13 \frac{1}{3}$
$= > \: \frac{9x + 4y}{6} = \frac{40}{3}$
$= > 9x + 4y = 80 \: \: - - (1)$
and,

$\frac{2}{3} x + \frac{3}{2} y = 8 \ \frac{1}{3}$
$= > \frac{4x + 9y}{6} = \frac{25}{3}$
$= > 4x + 9y = 50 \: \: - - (2)$
eq (1) - eq(2)
9x +4y = 80
4x+9y = 50
(-) (-). (-)

=> 5x - 5y = 30
=> 5(x-y) =30
=> x-y =6 ..... (3)

eq(1) +eq(2) , we get
13x+13y =130
=> 13(x+y) =130
=> x+y = 10. .... (4)

now, eq(3) +eq(4) , we get:
2x = 16
=> x =8
put this value in eq (3)
8-y =6
=> y =2