Question

Please solve this problem very urgent ll mark u as a brainy

Answer 1

1.
$3 {x}^{2} - 4 \sqrt{2} x - 30 = 0$
comparing with quadratic equation
ax²+bx+c=0
a=3
b=-4√2
c=-30
$x = \frac{ - ( - 4 \sqrt{2}) + - \sqrt{( - {4 \sqrt{2} }^{2} ) } - 4 \times 3 \times ( - 30)}{2 \times 3} \\ x = \frac{4 \sqrt{2} + - \sqrt{392} }{6} \\ x = \frac{4 \sqrt{2} + - 14 \sqrt{2} }{6} \\ x = \frac{4 \sqrt{2} + 14 \sqrt{2} }{6} orx = \frac{4 \sqrt{2} - 14 \sqrt{2} }{6} \\ x = \frac{3 \sqrt{2} }{1} orx = - \frac{5 \sqrt{2} }{3}$
2.
$4 {y}^{2} + 15 \sqrt{3} y + 42 = 0$

compairing with quadratic equation
ay²+by+c=0
a=4
b=15√3
c=42
$4 {y}^{2} + 15 \sqrt{3} y + 42 = 0 \\ y = \frac{ - ( 15 \sqrt{3}) + - \sqrt{ {(15 \sqrt{2} )}^{2} } - 4 \times 4 \times 42 }{2 \times 4} \\ y = \frac{ - 15 \sqrt{3} + - \sqrt{3} }{8} \\ y = \frac{ - 15 \sqrt{3} + \sqrt{3} }{8} or \: y = \frac{ - 15 \sqrt{3} - \sqrt{3} }{8} \\ y = - \frac{7 \sqrt{3} }{4} or \: y = - 2 \sqrt{3}$
hope this helps you:-))))
don't forget to do it brainleist.