Question

please solve this qn of maths...​

Answer 1

GIVEN:

$\implies \: \bf \: \tan ^{ - 1} \bigg[ 2 \sin \bigg(2 \cos ^{ - 1} \frac{ \sqrt{3} }{2} \bigg) \bigg]$

TO FIND:

$\bf \: to \: find \: the \: value \: of \: ... \: \bf \: \tan ^{ - 1} \bigg[ 2 \sin \bigg(2 \cos ^{ - 1} \frac{ \sqrt{3} }{2} \bigg) \bigg]$

SOLUTION:

$\implies \: \bf \: \tan ^{ - 1} \bigg[ 2 \sin \bigg(2 \cos ^{ - 1} \frac{ \sqrt{3} }{2} \bigg) \bigg] \\ \\ \implies \: \: \ \: \bf \: \tan ^{ - 1} \bigg[ 2 \sin \bigg(2 \cos ^{ - 1} \bigg( \cos \frac{ \pi }{6} \bigg) \bigg) \bigg]$

Cancelling cos from cos we get ,

$\implies \: \bf \: \tan ^{ - 1} \bigg[ 2 \sin \bigg(2 \bigg( \frac{ \pi }{6} \bigg) \bigg)\bigg] \\ \\ \implies \: \bf \: \tan ^{ - 1} \bigg[ 2 \times \frac{ \sqrt{3} }{2} \bigg] \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \:or \: \\ \\ \implies \: \tan^{ - 1} ( \sqrt{3} ) = \frac{\pi}{3}$

Answer 2

Hi Aadishree..,.....

.

why you left.....