Question

please solve this quadratic equation question..

let the α,β be the roots of equation
(x - α)(x-β) = c , cnot equal to zero ,
then the roots of equation (x - α)(x-β) + c = 0 are ???

Answer 1

hello mate,

Given,

α, β are the roots of

equation (x - α)(x-β) = c.

➡ (x - α)(x-β) - c = (x - α)(x-β)

➡(x - α)(x-β) = (x - α)(x-β) + c

•°• As we know that ,

➡a, b are the roots of equation (x - α)(x-β) + c = 0.

➡So, A and B are the roots of the equation.

Answer 2

$<b>Hello Friend<b>$ ❤️❤️

The answer of u r question is..✌️✌️

Ans:✍️✍️✍️✍️✍️✍️

Given,

$\alpha \: b \: are \: the \: roots$

Equation.


$(x - \alpha )(x - \beta ) = c$

So

$(x - \alpha )(x - \beta ) - c = (x - \alpha )(x - \beta )$



a and b are the roots of equation.


so,

A and B are the roots of equation.

Hope it helps uu buddy!!❤️

Thank you..☺️☺️