please solve this question
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So the number is 36 .......
take ones place be x and tense place be y ........
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Step-by-step explanation:
Let the digit at Ones place be 'y' and that at tens place be 'x'
Then, Number = 10x + y
Also, Number formed by interchanging the digits = 10y + x
ATQ
x + y = 9...............(1)
(10y +x) = (10x + y) + 27........... (2)
From (2), we get
10y -y = 10x-x + 27
9y = 9x +27
y = x + 3............ (3)
Put value from eq (1) in (3), we get
9-x=x+3
2x=6
x=3
Put x=3 in eq (3)
y=6
Therefore, Answer = 10x+y = 36
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