Question

please solve this question....

Answer 1

conductivity = 1.29 ohm^-1 m^-1
resistance ( 0.1 M ) = 100 ohm
then
k = 1/p = 1/R × l/A
l/A = R× k
( l/A) is cell constant = 100 × 1.29 m-¹
cell constant = 129 m-¹
here questions say about same cell hence cell constant is same for both condition .

we know,
molar conductivity = k×1000/M
where K is conductivity ,
now, for second case
k = cell constant/resistance
=129/520 ohm^-¹ m-¹

now,
molar conductivity = 129/520×1000/0.2
= {129/1040}× 10000

= 1240.38 ohm-¹ m² mol-¹


method 2 :-

cell constant = 1.29× 100 = 129

now ,
molar conductivity = K ×1000/M
=(129/520)× 1000/0.2
=1240.38 ohm-¹ m²mol-¹