please solve this question
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1) 3x^2+2ax-3=0;x=-1/2
3(-1/2)^2 +2a(-1/2)-3=0
3/4-a-3=0
-a=3-3/4
-a=8/4
[a=-2.]
2) kx^2 +√2x -4 =0;x=√2
k(√2)^2 + √2(√2)-4=0
k(2)+2-4=0
2k -2=0
2k=2
[ k=1]
3) ax^2 +bx + 1 = 0; x=1,2
a(1)^2 +b(1) + 1=0
a +b +1=0
a=-b-1 ----------(1)
a(2)^2 +b(2) +1 =0
4a +2b +1=0
4(-b-1)+2b +1=0. from eq (1)
-4b -4 + 2b +1=0
-2b =3
[b=-3/2]---------(2)
a=-b-1. from. eq (1)
a=-(-3/2)-1. from eq (2)
a=3/2-1
[a=1/2]
3(-1/2)^2 +2a(-1/2)-3=0
3/4-a-3=0
-a=3-3/4
-a=8/4
[a=-2.]
2) kx^2 +√2x -4 =0;x=√2
k(√2)^2 + √2(√2)-4=0
k(2)+2-4=0
2k -2=0
2k=2
[ k=1]
3) ax^2 +bx + 1 = 0; x=1,2
a(1)^2 +b(1) + 1=0
a +b +1=0
a=-b-1 ----------(1)
a(2)^2 +b(2) +1 =0
4a +2b +1=0
4(-b-1)+2b +1=0. from eq (1)
-4b -4 + 2b +1=0
-2b =3
[b=-3/2]---------(2)
a=-b-1. from. eq (1)
a=-(-3/2)-1. from eq (2)
a=3/2-1
[a=1/2]
akash92:
pls help in my question
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