Math, asked by alishaagra99, 1 year ago

please solve this question

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Answered by Vivi842
1
1) 3x^2+2ax-3=0;x=-1/2
3(-1/2)^2 +2a(-1/2)-3=0
3/4-a-3=0
-a=3-3/4
-a=8/4
[a=-2.]


2) kx^2 +√2x -4 =0;x=√2
k(√2)^2 + √2(√2)-4=0
k(2)+2-4=0
2k -2=0
2k=2
[ k=1]

3) ax^2 +bx + 1 = 0; x=1,2

a(1)^2 +b(1) + 1=0
a +b +1=0
a=-b-1 ----------(1)


a(2)^2 +b(2) +1 =0
4a +2b +1=0
4(-b-1)+2b +1=0. from eq (1)
-4b -4 + 2b +1=0
-2b =3
[b=-3/2]---------(2)

a=-b-1. from. eq (1)

a=-(-3/2)-1. from eq (2)
a=3/2-1
[a=1/2]


akash92: pls help in my question
Vivi842: ask
akash92: You are Rekha living at S-453 Raghupura, New Delhi. Some women have been robbed of their gold chains and earrings in the main market of your block during rush hours by young boys riding bike. You are very much worried about such incidents. Write a letter to the Editor of a local newspaper to draw attention of the authority concerned about it.
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