please solve this question
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here given,
=) x^2 - (7 - i ) x + (18 - i ) = 0
=) x^2 - 7x + ix + 18 - i = 0
=)( x^2 - 7x + 18) + i( x - 1) = 0
not this is of the form a + ib = 0
so equating real and imaginary party equal to zero.
=) x^2 -7x +18 =0 & (x - 1 ) = 0
so here x = 7 +_ √ 49 - 4×18 / 2
x = (7 +_ i√23 )/2 & x - 1 = 0
so. x = 1
there is 3 solution,
x = (7+_ i√23 )/2 , 1
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=) x^2 - (7 - i ) x + (18 - i ) = 0
=) x^2 - 7x + ix + 18 - i = 0
=)( x^2 - 7x + 18) + i( x - 1) = 0
not this is of the form a + ib = 0
so equating real and imaginary party equal to zero.
=) x^2 -7x +18 =0 & (x - 1 ) = 0
so here x = 7 +_ √ 49 - 4×18 / 2
x = (7 +_ i√23 )/2 & x - 1 = 0
so. x = 1
there is 3 solution,
x = (7+_ i√23 )/2 , 1
________________________________________
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