Question

Please solve this question ​

Answer 1

equivalent resistance between AC

2+4 =6ohm (AB+BC) are in parrel

3+6=9Ohm. ( AD+ DC)

so,.

1/R=1/6+1/9

1/R=3+2/18

R=18/5=3.6 ohm

total resistance of circuit is 3.6+.4= 4 ohm

so,

I = 6v/4ohm=1.5A

Now ,we know in path ABC and ADC

current I divides to I1 and I2

so,. I = I1+I2

Vac = 3.6*I

Vac=3.6*1.5

Now, I1=Vac/Rabc= 3.6*1.5/2+4= .9A

I2 =Vac/Radc= 3.6*1.5/3+6=.6A