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Maximum acceleration exists between 30s and 40s
a = (v - u)/t
a = (80 - 20) / (40 - 30)
a = 6m/s^2
S = ut + 0.5at^2
S = 20*10 + 0.5*6*100
S = 200 + 300
S = 500m
Answers are
1. Maximum acceleration = 6 m/s^2
2. Distance travelled in that interval = 500m
a = (v - u)/t
a = (80 - 20) / (40 - 30)
a = 6m/s^2
S = ut + 0.5at^2
S = 20*10 + 0.5*6*100
S = 200 + 300
S = 500m
Answers are
1. Maximum acceleration = 6 m/s^2
2. Distance travelled in that interval = 500m
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