Question

please solve this question ​

Answer 1

${}{ \huge{ \bold{ \star{ \underline{solution}}}}}$

We know that,

∠ACB = angle APB/2

∠ACB = 150/2

∠ACB = 75°

Since,

ACD is a straight line, so

∠ACB + ∠BCD = 180°

75° + ∠BCD = 180°

∠BCD = 180° – 75°

= 105°

Now,

∠BCD = Reflex ∠BQD

105°= (360°- ∠BQD)

210° = 360° - ∠BQD

∠BQD = 360°– 210°

Therefore,

∠BQD = 150°

Mark it brainlist.....

Hope it helps you ❣️☑️