Physics, asked by debosmitaBarman, 11 months ago

please solve this question​

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Answered by anjali30703
0

Answer:

Option number (4) is the correct answer .

Work function of the metal is hc/15 lamda.

Explanation:

Here,

h is the planks constant.

c is the speed of light.

KE is the kinetic energy.

Vs is the stopping potential.

lamda is the wavelength of incident light.

CASE 1

(lamda)1 is the wavelength of of incident light in first case.

Vs1 is the stopping potential in first case.

CASE 2

(lamda)2 is the wavelength of of incident light in second case.

Vs2 is the stopping potential in second case.

Hence,

Work function of the metal is hc/15 lamda.

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