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Answered by
1
(a+b+c)² = a²+b²+c²+2ab+2bc+2ca
(9)² = a²+b²+ c²+2(ab+bc+ca)
81 = a²+b²+c²+ 2(40)
81-80 = a²+b²+c²
1 = a²+b²+c²
hope this helps
(9)² = a²+b²+ c²+2(ab+bc+ca)
81 = a²+b²+c²+ 2(40)
81-80 = a²+b²+c²
1 = a²+b²+c²
hope this helps
Answered by
1
we know that,
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
so,
a²+b²+c²=(a+b+c)²-2(ab+bc+ca)
a²+b²+c²=(9)²-2(40)
a²+b²+c²=81-80
a²+b²+c²=1
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
so,
a²+b²+c²=(a+b+c)²-2(ab+bc+ca)
a²+b²+c²=(9)²-2(40)
a²+b²+c²=81-80
a²+b²+c²=1
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