Question

please solve this question ​

Answer 1

Answer:

Answer:

Let the width of the gravel path be w m.

Length of the rectangular field = 50 m

Breadth of the rectangular field = 40 m

Let the length and breadth of the flower bed be x m and y m respectively.

Therefore, we have:

x + 2w = 50 ... (1)

y + 2w = 40 ... (2)

Also, area of rectangular field = 50 m × 40 m = 2000 m^2

Area of the flower bed = xy m^2

Area of gravel path = Area of rectangular field - Area of flower bed = (2000 - xy) m^2

Cost of laying flower bed + Gravel path = Area × cost of laying per sq. m

∴ 52000 = 30 × xy + 20 × (2000 − xy)

52000 = 10xy + 40000

xy = 1200

using(1) and (2), we have:

(50-2w)(40-2w)=1200

2000-180w+800=0

w^2-45w+200=0

(w-5)(w-40)=0

w=5,40

If w = 40, then x = 50 − 2w = − 30, which is not possible. Thus, the width of the gravel path is 5 m.

Step-by-step explanation: