Question

please solve this question​

Answer 1

$LHS=\sqrt{\frac{1+sinA}{1-sinA} } \\\\=\sqrt{\frac{1 +sinA}{1-sinA}*\frac{1+sinA}{1+sinA} }\\ \\=\sqrt{\frac{(1+sinA)^2}{1^2-(sinA)^2} } \\\\= \frac{1+sinA}{\sqrt{1-sin^2A} } \\\\=\frac{1+sinA}{\sqrt{cos^2A} }\\ \\=\frac{1+sinA}{cosA}\\ \\=\frac{1}{cosA}+\frac{sinA}{cosA}\\ \\=secA+tanA$

LHS=RHS

Hence, proved.

Answer 2

Answer:

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or kse h ye v btana