Question

please solve this question...​

Answer 1

Answer:

According to the principle of dimensional homogeneity,

Dimension of v = Dimension of At² = Dimension of Bt

Now,

• Dimension of A = (Dimension of v)/t²

→ [LT⁻¹] / [T²]

→ [LT⁻¹] × [T⁻²]

→ [LT⁻³]

→ [M⁰L¹T⁻³]

• Dimension of B = (Dimension of v)/t

→ [LT⁻¹] / [T]

→ [LT⁻¹] × [T⁻¹]

→ [LT⁻²]

→ [M⁰L¹T⁻²]

Hence, the dimension of A is [M⁰L¹T⁻³] and dimension of B is [M⁰L¹T⁻²].

Answer 2

Answer:

I HOPE THAT IT'S HELPFUL FOR YOU.