Question

please solve this question ​

Answer 1

Answer:

$\huge\bold\pink\star\green{ANSWER :-}$

Step-by-step explanation:

${x}^{2} - 8x + 12 = (x - 6)(x - 2)$

Answer 2

$\sf{\underline{\boxed{\green{\large{\bold{ Correct \: Question}}}}}}$

• solve the equation using formulae $\sf x^2 - 8x + 12 = 0$

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$\sf{\underline{\boxed{\green{\large{\bold{ Solution}}}}}}$

$\sf\implies x^2 - 8x + 12 = 0$

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• compare the eq with $\sf{\underline{\bold{ax^2 + bx + c = 0 }}}$

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☯ a = 1

☯ b = -8

☯ c = 12

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now :-

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$\sf{\underline{\boxed{\pink{\large{\mathfrak{x = \dfrac{ - b \pm \sqrt D }{2a }}}}}}}$

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$\sf{\underline{\boxed{\pink{\large{\mathfrak{ D = b^2 - 4ac }}}}}}$

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• finding value of D.

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$\sf\implies D = b^2 - 4ac$

$\sf\implies D = (-8)^2 - 4 \times 1 \times 12$

$\sf\implies D = 64 - 48$

$\sf\implies D = 16$

$\sf{\underline{\boxed{\blue{\large{\bold{ D = 16 }}}}}}$

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• putting values in the eq.

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$\sf\implies x = \dfrac{ -b \pm\sqrt D }{2a}$

$\sf\implies x = \dfrac{ -( -8) \pm\sqrt {16} }{2\times 1 }$

$\sf\implies x = \dfrac{ 8 \pm 4 }{2}$

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✒$\sf x = \dfrac{ 8 + 4 }{ 2 }$

$\implies x = \dfrac {12}{2}$

$\implies x = 6$

$\sf{\underline{\boxed{\purple{\large{\bold{ x = 6 }}}}}}$

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✒$\sf x = \dfrac{ 8 - 4 }{ 2 }$

$\implies x = \dfrac {4}{2}$

$\implies x = 2$

$\sf{\underline{\boxed{\purple{\large{\bold{ x = 2 }}}}}}$

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$\sf{\underline{\boxed{\purple{\large{\bold{ x = 6 \: or \: 2 }}}}}}$