PLEASE SOLVE THIS QUESTION
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in ∆ABC,
AB=AC
<ABC=<ACB(angle oppo. to equal sides of a ∆ are equal)---------(1)
in ∆BOC,
OB=OC
<OBC=<OCB---------(2)
Adding equation 1 and 2,we get
<ABC+<OBC=<ACB+<OCB
<ABO=<ACO[PROVED]
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mad brains
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