please solve this question.
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hey dearie! here is your answer...
hope this helps!!:)
hope this helps!!:)
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If rq=pq and angle qpr=qpr but how can u say that angle pqr will 90
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For the first one we know that DR=CQ=BP and it is a square
So,AB=BC=CD=DA
DR=CQ.......1
DC=CB.....2
Subtract 1 from 2
We get dr-dc=cq-cb
Which will give RC=QB........3
2nd one
We have to prove rq=pq
So,in tri.rcq and pbq we have,
RC=QB from ..3
BP=CQ given
And angle RCQ=PBQ each 90
By SAS both are equal
By CPCT RQ=PQ .....
Sorry I am little confused about 3 one I will tell u after Ward's
But in 4rt one
If u proved that angle par is 90 then ,we know that pq=rq
So,angle qpr=qpr
Let the angle be X
X+X+90=180
2X=180-90
2X=90
X=90/2
X=45
Angle RPQ=45
So,AB=BC=CD=DA
DR=CQ.......1
DC=CB.....2
Subtract 1 from 2
We get dr-dc=cq-cb
Which will give RC=QB........3
2nd one
We have to prove rq=pq
So,in tri.rcq and pbq we have,
RC=QB from ..3
BP=CQ given
And angle RCQ=PBQ each 90
By SAS both are equal
By CPCT RQ=PQ .....
Sorry I am little confused about 3 one I will tell u after Ward's
But in 4rt one
If u proved that angle par is 90 then ,we know that pq=rq
So,angle qpr=qpr
Let the angle be X
X+X+90=180
2X=180-90
2X=90
X=90/2
X=45
Angle RPQ=45
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