please solve this question
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2sin2teta=root3
sin2tera=root3/2
2teta=sin inverse (root3/2)
2teta=pi/3
teta= pi/6
cospi/3=1/2
sin2tera=root3/2
2teta=sin inverse (root3/2)
2teta=pi/3
teta= pi/6
cospi/3=1/2
Answered by
1
The question was in two ways as it wasn't clear that 2 is exponent power or complete integer....
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pranav112:
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it's ok
I was unable to understand the question clearly
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haryana
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tamil nadu
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