Question

please solve this question

Answer 1

sin²a +[1/(1+tan²a)

Now from identity 1+tan²a= sec²a,

sin²a+(1/sec²a).....(from above identity)

as we know (1/sec a)= cos a so,
also, (1/sec²a) = cos a

So, sin²a+ cos² a= 1 ( identity sin²a+cos²a = 1)

1= Ans




hope this helps you

Answer 2

=sin²Ф+1/1+tan²Ф
=sin²Ф+1/sec²Ф             (from identity 1+tan²Ф=sec²Ф)
=sin²Ф+cos²Ф                (as 1/secФ=cosФ then 1/sec²Ф=cos²Ф)
=1                                  (from identity sin²Ф+cos²Ф=1)

:) Hope this helps!!!!!