Question

please solve this question​

Answer 1

Step-by-step explanation:

First area of tirangle PQR =1/2×b×h

1/2×24×7=84cm^2

For QR By pythogoras theorem

QR^2=PR^2+PQ^2

QR=25cm

Radius=25/2cm

Now area of semi circle=1/2×22/7×25/2×25/2

=6875/28vm^2

Area of shaded portion = area of semi circle - area of the t tirangle PQR

4875/28 - 84= 4523/28cm^2