Question

please solve this question

Answer 1

tri ACD ~TRI ABC
AS perpendicular drawn from the vertex
to hypotenuse than tri both side of per are similar.
so AC/AB = AD /AC
Cross mult
AC^2= AB.AD 1..
SIMILARLY
in tri BCD ~ tri BAC
(SAME AS FIRST )
so BC/BA = BD /BC (CROSS MULT)
BC^2= BA . BD 2..
from 1 and 2 , we get
BC^2 BA . BD BD
____ = _______ = ___
AC^2 AB . AD AD

Answer 2

Hope u can understand