Please solve this question
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this is the answer of your questions
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regmikritika12:
we have to find the equation
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Sorry! in pic, i hv done a blunder.
See., first rearrange the eqn i.e., given eqn becomes : 5y+4x-11=0
Now,
m1 = -4/5 and m2 becomes= 5/4 [m1m2= -1]
Now.,
put the point(2,3) and 'm2' (or 'm' say)= 5/4 in eqn "y=mx+c"
Thus we find the value of 'c' i.e., c = 1/2
Now,
put c = 1/2 in eqn Y = (5/4)x + c
i.e., y=(5/4)x + 1/2
then,the required eqn becomes 5x - 4y + 2 = 0
See., first rearrange the eqn i.e., given eqn becomes : 5y+4x-11=0
Now,
m1 = -4/5 and m2 becomes= 5/4 [m1m2= -1]
Now.,
put the point(2,3) and 'm2' (or 'm' say)= 5/4 in eqn "y=mx+c"
Thus we find the value of 'c' i.e., c = 1/2
Now,
put c = 1/2 in eqn Y = (5/4)x + c
i.e., y=(5/4)x + 1/2
then,the required eqn becomes 5x - 4y + 2 = 0
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as per the book , answer is 5x-4y+2=0 though thanks for giving your time
it's OK
your question is okay?
uff
yeah i hv done a blunder.
wait!
Here , u can see in text.. i have just edited the amswer.
Thank you so much
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