please solve this question
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7
p(x)=p(1)
x^3-4x^2+5x-2
(1)^3-4(1)^2+5(1)-2
=1-4+5-2
6-6=0
P(x)=p(2)
(2)^3-4(2)^2+5(2)-2
8-16+10-2
18-18
=0 answer
x^3-4x^2+5x-2
(1)^3-4(1)^2+5(1)-2
=1-4+5-2
6-6=0
P(x)=p(2)
(2)^3-4(2)^2+5(2)-2
8-16+10-2
18-18
=0 answer
Answered by
3
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ans is 0
hope it helps u
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