Question

Please solve this Question

Answer 1

Here is your answer :

10x^2 - 27x + 5 = 0

Factorise by splitting the middle term.

10x^2 - 25x - 2x + 5 = 0

5x ( 2x - 5 ) - 1 ( 2x - 5 ) = 0

( 5x - 1 ) ( 2x - 5 ) = 0

5x - 1 = 0
x = 1 / 5

2x - 5 = 0
x = 5/2

So x = 1 / 5 or 5 / 2

Hope it helps.

Have a good day buddy.

Answer 2

Given Equation is 10x^2 - 27x + 5 = 0

10x^2 - 25x - 2x + 5 = 0

5x(2x - 5) - 1(2x - 5) = 0

(5x - 1)(2x - 5) = 0

(5x - 1) = 0, (2x - 5) = 0

x = 1/5, 5/2.


Verification:

When x = 1/5 :- 

10x^2 - 27x + 5 = 0

10(1/5)^2 - 27(1/5)  + 5 = 0

2/5 - 27/5 + 5 = 0

-5 + 5 = 0

0 = 0.


When x = 5/2 :- 

10x^2 - 27x + 5 = 0

10(5/2)^2 - 27(5/2) + 5 = 0

125/2 - 135/2 + 5 = 0

-5 + 5 = 0

0 = 0.



Hope this helps!