Question

Please solve this question.

Answer 1

4

Step-by-step explanation:

$\frac{{a}^{2n - 3} \times ( {a}^{2}) {}^{n + 1} }{( {a}^{4} ) {}^{ - 3} } = \frac{( {a}^{3} ) {}^{3} }{ ({a}^{6} ){}^{ - 3} }$

$\frac{ {a}^{2n - 3 + 2n + 2} }{ {a}^{ - 12} } = \frac{ {a}^{9} }{ {a}^{ - 18} }$

${a}^{4n - 1 - ( - 12)} = {a}^{9 - ( - 18)}$

${a}^{4n - 1 + 12} = {a}^{9 + 18}$

${a}^{4n + 11} = {a}^{27}$

comparing power both sides,

we get,

4n +11 = 27

4n = 27 - 11

4n = 16

n = 16/4 = 4

n = 4