please solve this question
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Hello you image say The Roots that's all we see
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Hey!!!!
Let's solve
=> x + 1/x = 3
=> x² + 1 = 3x
=> x² - 3x + 1 = 0
Thus D = b² - 4ac
=> D = (3)² - 4(1)(1)
=> D = 9 - 4
Thus D > 0
Thus roots are real and distinct
Hope this helps
Let's solve
=> x + 1/x = 3
=> x² + 1 = 3x
=> x² - 3x + 1 = 0
Thus D = b² - 4ac
=> D = (3)² - 4(1)(1)
=> D = 9 - 4
Thus D > 0
Thus roots are real and distinct
Hope this helps
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