Please solve this question
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tan A = 4/3
TF
(4cos A - sin A)/(2cos A + sin A)
divide numerator and denominator by cos A
(4 - tan A)/(2 + tan A)
(4- 4/3)/(2+4/3)
(8/3)/(10/3)
(8/10)
4/5 Ans
TF
(4cos A - sin A)/(2cos A + sin A)
divide numerator and denominator by cos A
(4 - tan A)/(2 + tan A)
(4- 4/3)/(2+4/3)
(8/3)/(10/3)
(8/10)
4/5 Ans
Answered by
2
hope this help........
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