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ans. x =38 , y = 13
These values of x & y are not unique.
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Applying division lemma to 81and 237, we get 237= 81*2+75 Since the remainder 75≠0. So, consider the divisor 81 and the remainder 75 and apply division lemma to get 81=75*1+6.
We consider the new divisor 75 and the new remainder 6 and apply division lemma to get, 75=6*12+3
We consider the new divisor 6 and the new remainder 3 and apply division lemma to get, 6=3*2+0
The remainder at this stage is zero.To represent the as a linear combination of the given two numbers, we start from the last but one step and successively eliminate the previous remainder as follows: From,we have
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We consider the new divisor 75 and the new remainder 6 and apply division lemma to get, 75=6*12+3
We consider the new divisor 6 and the new remainder 3 and apply division lemma to get, 6=3*2+0
The remainder at this stage is zero.To represent the as a linear combination of the given two numbers, we start from the last but one step and successively eliminate the previous remainder as follows: From,we have
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