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(a+b+c)^2=a^2+b^2+c^2+2[ab+bc+ca]
(1/4a-1/2b+1)^2
= 1/16a^2+1/4b^2+1+2(-1/8ab-1/2b+1/4a)
=1/16a^2+1/4b^2+1-1/4ab-b+1/2a
(1/4a-1/2b+1)^2
= 1/16a^2+1/4b^2+1+2(-1/8ab-1/2b+1/4a)
=1/16a^2+1/4b^2+1-1/4ab-b+1/2a
bhullargursahibsingh:
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it is the answer according to me
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yes ,it is statement
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