Question

please solve this Question

Answer 1

you should ask this question in math side

Answer 2

Hope u like my process
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Integrating them we get,
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$= > ( \frac{ {x}^{3} }{3} + 2 \times \frac{ {x}^{2} }{2} + 3x) \\ where \: we \: \: put \: \: the \: lower \: and \: upper \: limits \: at \: place \: of \: x \\ \\ = ( \frac{ {3}^{3} }{3} + {3}^{2} + 3 \times 3) - ( \frac{ {2}^{3} }{3} + {2}^{2} + 3 \times 2) \\ \\ = 9 + 9 + 9 - \frac{8}{3} - 4 - 6 \\ \\ = 17 - \frac{8}{3} = \frac{51 - 8}{3} \\ = \frac{43}{3} = 14 \frac{1}{3}$
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