Question

please solve this question​

Answer 1

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Adb-140

Answer 2

Answer

In given figure ABCD is a rhombus. We know that diagonals of rhombus bisect each other perpendicularly.

Hence, ∠BOC= 90∘

∠OCB = 40∘  (Given)

AD∥BC and BD is the transversal   --- (Opposite sides of rhombus are parallel to each other)

∴ ∠ADB = ∠DBC   ---- (Alternate angles)

In △OBC,

∠BOC + ∠OCB + ∠OBC = 180∘

⇒  90∘+ 40∘ + ∠OBC = 180∘

⇒  ∠OBC =180∘ - 130∘

∴  ∠OBC = 50∘

But ∠OBC =∠DBC

∴  ∠ADB = 50∘   ---( Alternate angle)

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