Question

please solve this question

Answer 1

(x+2)^2+5(x+2)
+x+2{(x+2)+5}
=(x+2)(x+7)
=x^2+7x+2x+14
=x(x+2)+7(x+2)
(x+2)(x+7)=0
this implies that ,
x+2=0 ,x+7=0
so,
x=-2 ,x=-7
x=-2,-7 are the roots of given equation !

Answer 2

the Ans will be (x+7)(x+2)