please solve this question
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rate of change of velocity= acceleration
At highest point acceleration = 10 m/sec^2
At highest point acceleration = 10 m/sec^2
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☆☆ AS-SALAMU-ALUKUM ☆☆
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REQUIRED :-
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MAGNITUDE OF RATE OF CHANGE OF VELOCITY MEANS V/t THAT MEANS ACCELERATION
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SO ACCELERATION AT HIGHEST POINT IS EQUAL TO '9.8m/s^2' OR AS IT IS GIVEN g=10m/s^2 SO ACCELERATIONWILLBE EQUAL TO 10m/s^2
●●●●●●●●●●●●●●●●●●●●●●
♡♤♡ INSHALLAH IT WILL HELP U ♡♤♡
●●●●●●●●●●●●●●●●●●●●●
REQUIRED :-
▪▪▪▪▪▪▪▪▪
MAGNITUDE OF RATE OF CHANGE OF VELOCITY MEANS V/t THAT MEANS ACCELERATION
●●●●●●●●●●●●●●●●●●●●●●
SO ACCELERATION AT HIGHEST POINT IS EQUAL TO '9.8m/s^2' OR AS IT IS GIVEN g=10m/s^2 SO ACCELERATIONWILLBE EQUAL TO 10m/s^2
●●●●●●●●●●●●●●●●●●●●●●
♡♤♡ INSHALLAH IT WILL HELP U ♡♤♡
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