Math, asked by kaushik8946, 1 year ago

please solve this question

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Answered by littyissacpe8b60
1

Class                     Frequency               fixi

0-5                          5                              5

10-20                       25                         30 (cf)

20-30                       P(f)                       30 + P

30-40                       18                          48 + P

40-50                         7                         55 + P

Total (n)                   50


So n = 55 + P

median is 24 which lies between 20 and 30

So median class is 20-30

Lower limit median class (l) = 20

Cumulative frequesncy (cf) = 30

Frequency median class f = P

Class size h= 10

24 = 20 +  [(55 +P)/2 - 30]    x   10

                        P


24 = 20 + [  55+p) - 60   ]x 5

                          P


4P  = (-5 + p) 5

4P = -25 + 5p

P = 25

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