please solve this question
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2. 153 degrees
3.95 degrees
3.95 degrees
krishna1833:
kese
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hey here is ur answer :
1. Given that,
AB ll CD
CD ll EF
And p and q are the transversal
Now,
angle x + 57° = 180 °
angle x = 180 ° - 57 °
angle x = 123 ° ( ans )
2. 145°+ angle a = 180 ° (linear pair )
angle a = 180° -145 °
angle a = 35 °
Now , angle a + angle c = 130 °
=>35°+angle c = 130°
=> angle c = 130 °- 35°
=>angle c = 95 °(ans)
Hope this will help u ...
Thanks ...
1. Given that,
AB ll CD
CD ll EF
And p and q are the transversal
Now,
angle x + 57° = 180 °
angle x = 180 ° - 57 °
angle x = 123 ° ( ans )
2. 145°+ angle a = 180 ° (linear pair )
angle a = 180° -145 °
angle a = 35 °
Now , angle a + angle c = 130 °
=>35°+angle c = 130°
=> angle c = 130 °- 35°
=>angle c = 95 °(ans)
Hope this will help u ...
Thanks ...
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