Question

please solve this question

Answer 1

The answer is :-

$\dfrac{1}{3}$

Please refer the above photograph for the used process.

Hope this will be helping you!


KEY POINTS TO REMEMBER :-

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$\tan( \alpha ) = \frac{ \sin( \alpha ) }{ \cos( \alpha ) }$

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$1 + { \tan}^{2} \alpha = { \sec}^{2} \alpha$

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$\dfrac{1}{ \cos( \alpha ) } = \sec( \alpha )$

Thanks!