please solve this question
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i dont know man seriously i am in 6th standerd
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Step-by-step explanation:
Given Equation is sin⁶θ + cos⁶θ:
= (sin²θ)³ + (cos²θ)³
We know that a³ + b³ = (a + b)(a² - ab + b²)
= (sin²θ + cos²θ)(sin⁴θ + cos⁴θ - sin²θcos²θ)
= (1)(sin⁴θ + cos⁴θ - sin²θcos²θ)
= (sin⁴θ + cos⁴θ - sin²θcos²θ)
= (sin⁴θ + cos⁴θ - sin²θcos²θ + 2sin²θcos²θ - 2sin²θcos²θ)
= (sin⁴θ + cos⁴θ + 2sin²θcos²θ - sin²θcos²θ - 2sin²θcos²θ)
= (sin⁴θ + cos⁴θ + 2sin²θcos²θ) - sin²θcos²θ - 2sin²θcos²θ
= (sin²θ + cos²θ)² - 3sin²θcos²θ
= 1 - 3sin²θcos²θ
Hope it helps!
thakursaab95:
thanks Bhai
Welcome :-)
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