Question

please solve this question

Answer 1

i dont know man seriously i am in 6th standerd

Answer 2

Step-by-step explanation:

Given Equation is sin⁶θ + cos⁶θ:

= (sin²θ)³ + (cos²θ)³

We know that a³ + b³ = (a + b)(a² - ab + b²)

= (sin²θ + cos²θ)(sin⁴θ + cos⁴θ - sin²θcos²θ)

= (1)(sin⁴θ + cos⁴θ - sin²θcos²θ)

= (sin⁴θ + cos⁴θ - sin²θcos²θ)

= (sin⁴θ + cos⁴θ - sin²θcos²θ + 2sin²θcos²θ - 2sin²θcos²θ)

= (sin⁴θ + cos⁴θ + 2sin²θcos²θ - sin²θcos²θ - 2sin²θcos²θ)

= (sin⁴θ + cos⁴θ + 2sin²θcos²θ) - sin²θcos²θ - 2sin²θcos²θ

= (sin²θ + cos²θ)² - 3sin²θcos²θ

= 1 - 3sin²θcos²θ

Hope it helps!