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1
Given:
f=10cm
u=15cm
Therefore object is placed between 2F1 and F1.
1/f=1/v+1/u
1/v=1/f-1/u
1/v=1/-10 - 1/-15
1/v=-1/10+1/15
=-3+2/30.
1/v =-1/30
v=-30cm
NATURE:
1)real
2) inverted
Answered by
0
The nature of the image is real
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