.please solve this question
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let, the boxes at first were be X
then, 50 boxes added. therefore X+50
then half boxes used. therefore (X+50)/2
at last 40 boxes left. therefore the equation is
(X+50)/2=40
X+50=40×2
X+50=80
X=80-50
X=30
Therefore, 30 boxes were there at initial.
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80
Step-by-step explanation:
Boxes=x
Boxes bought extra=50
X+50/2=40
X+50=80
X=80-50
X=30
X+50=30+50=80
No of boxes at beggining=80
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