Math, asked by shourya052, 1 year ago

.please solve this question​

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Answers

Answered by Jhapsa
0

let, the boxes at first were be X

then, 50 boxes added. therefore X+50

then half boxes used. therefore (X+50)/2

at last 40 boxes left. therefore the equation is

(X+50)/2=40

X+50=40×2

X+50=80

X=80-50

X=30

Therefore, 30 boxes were there at initial.

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Answered by Anonymous
0

Answer:

80

Step-by-step explanation:

Boxes=x

Boxes bought extra=50

X+50/2=40

X+50=80

X=80-50

X=30

X+50=30+50=80

No of boxes at beggining=80

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