please solve this question
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Heya©®©®
_______________________________
AB + AC = 15
AC = 15 - AB
AC = 15 - h
=>
In Trangle ABC
Sin (60) = h/ AC
=>
√3/2 = h/ ( 15 - h )
=>
15√3 - h√3 = 2h
=>
h ( 2 + √3 ) = 15√3
=>
h = 15√3 / ( 2 + √3 )
=>
h =( 15 × 1.73 ) / ( 2 + 1.73 )
=>
h = 6.95m
So, the tree breaks at a height of 6.95m
_______________________________
AB + AC = 15
AC = 15 - AB
AC = 15 - h
=>
In Trangle ABC
Sin (60) = h/ AC
=>
√3/2 = h/ ( 15 - h )
=>
15√3 - h√3 = 2h
=>
h ( 2 + √3 ) = 15√3
=>
h = 15√3 / ( 2 + √3 )
=>
h =( 15 × 1.73 ) / ( 2 + 1.73 )
=>
h = 6.95m
So, the tree breaks at a height of 6.95m
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